In: Statistics and Probability
Consider the following data representing the daily calorie intake for dieters.
13801380, 10321032, 13181318, 10251025, 10211021, 12541254, 14181418, 14251425, 11911191, 10601060, 11701170, 14171417, 11901190, 12601260, 10541054, 13931393, 10651065, 13851385, 10671067, 12671267, 13461346
Copy Data
Class | Frequency | Class Boundaries | Midpoint | Relative Frequency | Cumulative Frequency |
---|---|---|---|---|---|
1002–10811002–1081 | |||||
1082–11611082–1161 | |||||
1162–12411162–1241 | |||||
1242–13211242–1321 | |||||
1322–14011322–1401 | |||||
1402–14811402–1481 |
Step 1 of 7: Determine the class width of the classes listed in the frequency table.
Step 2 of 7: Determine the frequency of the second class.
Step 3 of 7: Determine the lower class boundary for the third class.
Step 4 of 7: Determine the upper class boundary for the third class.
Step 5 of 7: Identify the midpoint of the fourth class.
Step 6 of 7: Calculate the relative frequency of the third class. Determine your answer as a simplified fraction.
Step 7 of 7: Compute the cumulative frequency of the sixth class.
class | frequency | class boundaries | midpoint | relative frequency | cumulative frequency | |
1002-1081 | 7 | 1001.5-1081.5 | 1041.5 | 1/3 | 7 | |
1082-1161 | 0 | 1081.5-1061.5 | 1121.5 | 0 | 7 | |
1162-1241 | 3 | 1161.5-1241.5 | 1201.5 | 1/7 | 10 | |
1242-1321 | 4 | 1241.5-1321.5 | 1281.5 | 4/21 | 14 | |
1322-1401 | 4 | 1321.5-1401.5 | 1361.5 | 4/21 | 18 | |
1402-1481 | 3 | 1401.5-1481.5 | 1441.5 | 1/7 | 21 |
from above given data:
Step 1 of 7: class width =80
Step 2 of 7: Determine the frequency of the second class =0
Step 3 of 7: Determine the lower class boundary for the third class =1161.5
Step 4 of 7: Determine the upper class boundary for the third class =1241.5
Step 5 of 7: Identify the midpoint of the fourth class =1281.5
Step 6 of 7: Calculate the relative frequency of the third class =3/21 =1/7
Step 7 of 7: Compute the cumulative frequency of the sixth class =18