In: Statistics and Probability
Assume a normal distribution and find the following
probabilities.
(Round the values of z to 2 decimal places. Round your
answers to 4 decimal places.)
(a) P(x < 17 | μ =
20 and σ = 3)
enter the probability of fewer than 17 outcomes if the mean is 20
and the standard deviation is 3
(b) P(x ≥ 61 | μ = 50
and σ = 8)
enter the probability of 61 or more outcomes if the mean is 50 and
the standard deviation is 8
(c) P(x > 45 | μ =
50 and σ = 5)
enter the probability of more than 45 outcomes if the mean is 50
and the standard deviation is 5
(d) P(16 < x < 19 |
μ = 18 and σ = 3)
enter the probability of more than 16 and fewer than 19 outcomes if
the mean is 18 and the standard deviation is 3
(e) P(x ≥ 75 | μ = 60
and σ = 2.79)
enter the probability of 75 or more outcomes if the mean is 60 and
the standard deviation is 2.79
Solution :
a) Given, X follows Normal distribution with,
= 20
= 3
Find P(X < 17)
= P[(X - )/ < (17 - )/]
= P[Z < (17 - 20)/3]
= P[Z < -1.00]
= 0.1587 ... ( use z table)
P(X < 17) = 0.1587
b) Given, X follows Normal distribution with,
= 50
= 8
Find P(X > 61)
= P[(X - )/ > (61 - )/]
= P[Z > (61 - 50)/8]
= P[Z > 1.38]
= 1 - P[Z < 1.38]
= 1 - 0.9162 ( use z table)
= 0.0838
P(X > 61) = 0.0838
c) Given, X follows Normal distribution with,
= 50
= 5
Find P(X > 45)
= P[(X - )/ > (45 - )/]
= P[Z > (45 - 50)/5]
= P[Z > -1.00]
= 1 - P[Z < -1.00]
= 1 - 0.1587 ( use z table)
= 0.8413
P(X > 45) = 0.8413
d) Given, X follows Normal distribution with,
= 18
= 3
Find, P(16 < x< 19)
= P(X < 19) - P(X < 16)
= P[(X - )/ < (19 - 18)/3] - P[(X - )/ < (16 - 18)/3]
= P[Z < 0.33] - P[Z < -0.67]
= 0.6293 - 0.2514 ..Use z table
= 0.3779
P(16 < x< 19) = 0.3779
e) Given, X follows Normal distribution with,
= 60
= 2.79
Find P(X > 75)
= P[(X - )/ > (75 - )/]
= P[Z > (75 - 60)/2.79]
= P[Z > 5.38]
= 1 - P[Z < 5.38]
= 1 - 1 ( use z table)
= 0.0000
P(X > 75) = 0.0000