In: Statistics and Probability
- a sample mean of 12.10 ounces and a sample standard deviation of 0.25 ounces.
(5) a. Set up a 95% confidence interval for the true population mean.
(10) b. At the 10% level, test the alternate hypothesis that the true mean is not equal to 12 ounces.
Pitcher |
Strikes |
Balls |
Total |
Bumgarner |
76 |
32 |
108 |
Cueto |
76 |
41 |
117 |
Bumgarner Cueto
Sample Mean (pitches per inning) 12.0 13.0
Sample Variance (pitches per inning) 3.5 8
Sample Size (# of innings) 9 9
(an “inning” is one of the rounds in a game)
(5) a. At the 99% level, test the alternate hypothesis that Cueto throws more pitches per inning than Bumgarner for the entire season (population of pitches):
(5) b. Set up a 90% confidence interval for the true difference in the proportion of Balls thrown by each pitcher for the entire season:
(5) c. Perform a hypothesis test to see if the proportion of throwing strikes for Bumgarner and Cueto is not equal for the entire season. Set the Type I error equal to 10%.
a)
Xbar +- t * s/sqrt(n)
b)
t-value based Population MEAN Hypothesis Test | |||||
xbar = sample mean = | 12.1 | ||||
s = sample standard deviation = | 0.25 | ||||
n = sample size = | 25 | ||||
α = alpha = | 0.1 | ||||
Step 1: State Ho and Ha | |||||
Population parameter comparison value? | 12 | ||||
Is this a LEFT, RIGHT or TWO tailed test? | TWO-tailed | ||||
Null Hypothesis: | Ho: µ = 12 | ||||
Alternate Hypothesis: | Ha: µ ≠ 12 | ||||
Step 2: State Decision Criteria; Find Critical Values | |||||
Reject Ho if t < -1.711 or t > 1.711 | |||||
or Reject Ho if p-value < α = 0.1 | |||||
Step 3: Calculate Test Statistic | |||||
Test statistic = t = | 2 | ||||
p-value = | 0.05693985 | ||||
Step 4: Make Decision | |||||
Reject Ho | |||||
Reject Ho since p-value (0.0569) IS less than α, alpha, = 0.1. | |||||
Also, Reject Ho since the Test statistic (2) meets the rejection criteria in STEP 2. | |||||
Step 5: Summarize Decision | |||||
There is sufficient statistical evidence to reject Ho. |
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