In: Statistics and Probability
(a) The 95% confidence interval for population mean is
where
degrees of freedom = 25-1=24
For 95% confidence with df = 24
critical value of t is , tc = 2.06 (from t table, critical value at 0.05 and df = 24)
Thus , 95% confidene interval for population mean is
= ( 11.897 , 12.203)
b)
The null and alternative hypothesis
12
12
Test statistic
12.10
S=0.25
= 2
df = n-1= 25-1=24
The two tailed critical value of t at 0.10 , with df =24 is tc = 1.71 (from t table)
Since calculated t > 1.71.
Reject H0
At 10% level of significance, there is sufficient evidence to conclude that mean is not equal to 12.