Question

With a growing aging population, the demand for hip replacement surgery in Canada has been increased in the last decade. The following table gives the distribution of the waiting time (in months) for hip replacement surgery in Ontario in 2013:

Percentage of patients/ Waiting time

10%/ 4 months
18%/ 5 months
53%/ 6 months
12%/ 7 months
7%/8 months

1. What is the probability that a randomly chosen patient who needs a hip replacement has to wait more than the average waiting time for this op- eration?

2. What is the standard deviation of two times the waiting time for this operation.

3. Find and graph the cumulative distribution function of the waiting time of a randomly chosen patient.

4. If the waiting time of a randomly chosen patient is at most 7 months, what is the probability that the waiting time falls between 4 and 6 months?

Answer 1

Answer:

Given that:-

Let X be the random variable denoting waiting time. Then its pmf is

X	4	5	6	7	8
P(X=x)	0.1	0.18	0.53	0.12	0.07

1) Average waiting time =E(X)=

=5.88

P(X>average waiting time)

2) Variance

  

Standard deviation of 2 times waiting time

3)Cumutative distribution is

4)We want to find

   

NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...

***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU