In: Statistics and Probability
The following data are from an experiment designed to investigate the perception of corporate ethical values among individuals who are in marketing. Three groups are considered: management, research and advertising (higher scores indicate higher ethical values).
Marketing Managers | Marketing Research | Advertising |
4 | 7 | 7 |
3 | 7 | 8 |
2 | 6 | 7 |
3 | 6 | 6 |
4 | 7 | 7 |
2 | 6 | 7 |
a. Compute the values identified below (to 2 decimal, if necessary).
Sum of Squares, Treatment | |
Sum of Squares, Error | |
Mean Squares, Treatment | |
Mean Squares, Error |
b. Use a=.05 to test for a significant difference in perception among the three groups.
Calculate the value of the test statistic (to 2 decimals).
Calculate Fisher's LSD value (to 2 decimals).
Test whether there is a significant difference between the means for marketing managers (1), marketing research specialists (2), and advertising specialists (3).
Difference | Absolute Value | Conclusion |
x1-x2 | ||
x1-x3 | ||
x2-x3 |
Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array): |
Source | SS | df | MS | F | P value |
Between | 57.00 | 2 | 28.500 | 57.0000 | 0.000 |
Within | 7.50 | 15 | 0.5000 | ||
Total | 64.50 | 17 |
a)
sum of sq;treatment= | 57.00 |
sum of sq; error= | 7.50 |
mean sq;treatment= | 28.50 |
mean square; error= | 0.50 |
b)
test statistic = | 57.00 |
p value is less than 0.01 | |
Conclude the treatment mean for the three groups are not all the same |
critical value of t with 0.05 level and N-k=15 degree of freedom= | tN-k= | 2.131 | |||
Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj) = | 0.87 |
Difference | Absolute Value | Conclusion |
x1-x2 | 3.50 | significant difference |
x3-x1 | 4.00 | significant difference |
x3-x2 | 0.50 | not significant difference |