Question

The following data are from an experiment designed to investigate the perception of corporate ethical values among individuals who are in marketing. Three groups are considered: management, research and advertising (higher scores indicate higher ethical values). Marketing Managers Marketing Research Advertising 10 5 7 9 5 8 8 4 7 9 4 6 10 5 7 8 4 7 Compute the values identified below (to 1 decimal, if necessary). Sum of Squares, Treatment 61 Sum of Squares, Error 7.5 Mean Squares, Treatment 30.5 Mean Squares, Error 0.5 Use = .05 to test for a significant difference in perception among the three groups. Calculate the value of the test statistic (to 2 decimals). 61 The p-value is What is your conclusion? Using = .05, determine where differences between the mean perception scores occur. Calculate Fisher's LSD value (to 2 decimals). 1.00 Test whether there is a significant difference between the means for marketing managers (1), marketing research specialists (2), and advertising specialists (3). Difference Absolute Value Conclusion 1 - 2 4.5 1 - 3 2 2 - 3 2.5

I only need this "Calculate Fisher's LSD value "

Answer 1

Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array):

Source	SS	df	MS	F	P value
Between	61.00	2	30.500	61.000	0.000
Within	7.50	15	0.5000
Total	68.50	17

a)

sum of sq;treatment=	61.00
sum of sq; error=	7.50
mean sq;treatment=	30.50
mean square; error=	0.50

test statistic =	61.00
p value is less than 0.01
Conclude the treatment mean for the three groups are not all the same

b)

critical value of t with 0.05 level and N-k=15 degree of freedom=				tN-k=	2.131
Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj)   =					0.87

Difference	Absolute Value	Conclusion
x1-x2	4.50	significant difference
x3-x1	2.00	significant difference
x3-x2	2.50	significant difference