In: Statistics and Probability
The following data are from an experiment designed to investigate the perception of corporate ethical values among individuals who are in marketing. Three groups are considered: management, research and advertising (higher scores indicate higher ethical values).
Marketing Managers | Marketing Research | Advertising |
9 | 7 | 6 |
8 | 7 | 7 |
7 | 6 | 6 |
8 | 6 | 5 |
9 | 7 | 6 |
7 | 6 | 6 |
a. Compute the values identified below (to 2 decimal, if necessary).
Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error
b. Use to test for a significant difference in perception among the three groups. Calculate the value of the test statistic (to 2 decimals). The p-value is? What is your conclusion?
c. Using , determine where differences between the mean perception scores occur. Calculate Fisher's LSD value (to 2 decimals). Test whether there is a significant difference between the means for marketing managers (1), marketing research specialists (2), and advertising specialists (3).
Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array): |
Source | SS | df | MS | F |
Between | 13.00 | 2 | 6.500 | 13.000 |
Within | 7.50 | 15 | 0.5000 | |
Total | 20.50 | 17 |
a)
sum of sq;treatment= | 13.00 |
sum of sq; error= | 7.50 |
mean sq;treatment= | 6.50 |
mean square; error= | 0.50 |
b)
test statistic = | 13.00 | ||
p value is less than 0.01 | |||
Conclude the treatment mean for the three groups are not all the same |
c)
critical value of t with 0.05 level and N-k=15 degree of freedom= | tN-k= | 2.131 | |||
Fisher's (LSD) for group i and j =(tN-k)*(sp*√(1/ni+1/nj) = | 0.87 |
Difference | Absolute Value | Conclusion |
x1-x2 | 1.50 | significant difference |
x3-x1 | 2.00 | significant difference |
x3-x2 | 0.50 | not significant difference |