An object is placed 37 cm in front of a converging lens. An image forms which...

An object is placed 37 cm in front of a converging lens. An image forms which has a magnification of 1.99 and is inverted. The object is then moved to 12.7 cm from the lens. What is the magnification of the image when it is moved there? Include a negative sign if inverted.

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Expert Solution

Answer: Magnification of the image is 2.0649 and since image is upright means erect hence i am not utting - ve sign as you have said to put negative sign if image is inverted

Here I am showing two ray diagrams in the scanned sheet.

In fig 1 it is shown the first case of the problem. Distances are randomly taken just to show that in first case image is inverted and in fig 2 second case is shown when object is moved to 12.7 cm Image is virtual and upright.

genius_generous answered 2 years ago

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