In: Statistics and Probability
Suppose that the weights of a certain type of bear are normally distributed with mean 332 lbs and standard deviation 24 lbs. If three such bears are randomly selected, find the probability that exactly two of them have a weight that is less than 354 lbs. (4 decimals) |
Solution :
Given that,
mean = = 332
standard deviation = = 24
n = 2
= 332
= / n = 24 / 2=16.97
P( < 354) = P[( - ) / < (354-332) / 16.97]
= P(z < 1.30)
Using z table
= 0.9032
probability= 0.9032