Question

In: Chemistry

A 1.05 gram sample of butter is refluxed with ethanolic KOH and required 10.4 mL of...

A 1.05 gram sample of butter is refluxed with ethanolic KOH and required 10.4 mL of 0.1875 M HCl to reach the phenolphthalein end point. If blank determination required 27.7 mL of the same standard acid, calculate the saponification value. Calculate the saponification number. Assuming butter comprised mainly of fat, what is its molar mass?

Solutions

Expert Solution

Assuming that butter comprises mainly of fat, the molar mass of the fat present should be equal to the amount of KOH it has neutralised = 173mg.


Related Solutions

You react 100.0 mL 1.01 M HBr(aq) with 99.1 mL of 1.05 M KOH(aq) solution. How...
You react 100.0 mL 1.01 M HBr(aq) with 99.1 mL of 1.05 M KOH(aq) solution. How many moles are actually neutralized? The density of each solution is 1.04 g/mL. Cpcal = 7.0 J/oC; Cs = 4.18 J/g·oC   The DT = 6.3 oC. Calculate q and DH/mole.
A) A 25 mL sample of 0.723M HClO4 is titrated with a 0.273M KOH solution. What...
A) A 25 mL sample of 0.723M HClO4 is titrated with a 0.273M KOH solution. What is the pH before any base is added? B) A 25 mL sample of 0.22M hydrazoic acid (HN3 ; Ka=2.6e-5) is titrated with a 0.30M KOH solution. What is the pH of the solution after 16 mL of base is added? C) A 25 mL sample of an HCl solution is titrated with a 0.15M NaOH solution. The equivalence point is reached with 75...
A 1.31 gram sample of an unknown monoprotic acid is dissolved in 50.0 mL of water...
A 1.31 gram sample of an unknown monoprotic acid is dissolved in 50.0 mL of water and titrated with a a 0.496 M aqueous sodium hydroxide solution. It is observed that after 9.16 milliliters of sodium hydroxide have been added, the pH is 7.227 and that an additional 14.6 mL of the sodium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? ____ g/mol (2) What is the value of Ka...
A 0.07420 gram sample of methyl amine was mixed with 125.0 mL of a HCl solution....
A 0.07420 gram sample of methyl amine was mixed with 125.0 mL of a HCl solution. The back-titration of the unreacted acid required 5.35 mL of 0.1057 M KOH to reach the equivalence point. Determine the molarity of the acid.
A 30.00 mL sample of 0.200 M HBr was titrated with 0.160 M KOH. a. What...
A 30.00 mL sample of 0.200 M HBr was titrated with 0.160 M KOH. a. What is the initial pH of the sample? b. What is the equivalence volume? c. What is the pH after 19.16 mL of KOH is added?
Consider the titration of a 34.0 mL sample of 0.170 M HBr with 0.200 M KOH....
Consider the titration of a 34.0 mL sample of 0.170 M HBr with 0.200 M KOH. Determine each of the following: 1. initial pH 2. the volume of added base required to reach the equivalence point 3. pH at 10.4 mL of added base 4. pH at the equivalence point
A 100.0 mL sample of 0.20 M HF is titrated with 0.20 M KOH. Determine the...
A 100.0 mL sample of 0.20 M HF is titrated with 0.20 M KOH. Determine the pH of the solution after the addition of 50.0 mL of KOH. The Ka of HF is 3.5 × 10-4. A. 2.08 B. 3.15 C. 4.33 D. 3.46 E. 4.15
Consider the titration of a 33.0 mL sample of 0.175 M HBr with 0.210 M KOH....
Consider the titration of a 33.0 mL sample of 0.175 M HBr with 0.210 M KOH. Determine each of the following: Part A the initial pH Express your answer using three decimal places. pH = Part B the volume of added base required to reach the equivalence point Express your answer in milliliters. V = Part C the pH at 11.0 mL of added base Express your answer using three decimal places. pH = Part D the pH at the...
A 25.0 mL sample of 0.30 M HCOOH is titrated with 0.20 M KOH. What is...
A 25.0 mL sample of 0.30 M HCOOH is titrated with 0.20 M KOH. What is the pH of the solution after 25.0 mL of KOH has been added to the acid? Ka = 1.8x10^-4
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the...
A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the pH of the solution after the addition of 200.0 mL of KOH. The Ka of HF is 3.5 × 10-4. Answer: 8.14 but how do I get this?? I'm so lost!
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT