In: Statistics and Probability
Suppose that the weights of a certain type of bear are normally distributed with mean 321 lbs and standard deviation 25 lbs. If three such bears are randomly selected, find the probability that exactly one of them has a weight that is less than 342 lbs.
answer correct to 4 decimal places
Solution :
Given that,
mean = = 321
standard deviation = = 25
n = 3
=321
= / n = 25/ 3=14.43
P( <342 ) = P[( - ) / < (342-321) /14.43 ]
= P(z <1.46 )
Using z table
= 0.9279
probability= 0.9279