In: Chemistry
A sample of Rh-105 (104.906 g/mol) has an activity of 4.89 x 1021 Bq. What mass of Rh-105 is lost after 7 minutes?
Calculate the answer ____________ g Rh-105 is lost.
Activity of sample = 4.89 x 1021 Bq
Activity of sample = 4.89 x 1021 Bq * (1 disintegrations per second (dps) / 1 Bq)
Activity of sample = 4.89 x 1021 dps
Time = 7 min
Time = 7 * (60 s / 1 min)
Time = 420 s
Total disintegrations = (Activity of sample) * (Time)
Total disintegrations = (4.89 x 1021 dps) * (420 s)
Total disintegrations = 2.05 x 1024 disintegrations
Total atoms lost = Total disintegrations
Total atoms lost = 2.05 x 1024 atoms
moles of Rh-105 lost = (Total atoms lost) / (Avogadro's number)
moles of Rh-105 lost = (2.05 x 1024 atoms) / (6.022 x 1023 atoms/mol)
moles of Rh-105 lost = 3.41 mol
mass of Rh-105 lost = (moles of Rh-105 lost) * (molar mass Rh-105)
mass of Rh-105 lost = (3.41 mol) * (104.906 g/mol)
mass of Rh-105 lost = 357.8 g