A 0.5070 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and...

A 0.5070 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and Ce(NO3)3 (molar mass = 326.13 g/mol) was dissolved in water. The solution was titrated with KIO3, producing the precipitates La(IO3)3 and Ce(IO3)3. For the complete titration of both La3+ and Ce3+, 42.10 mL of 0.1204 M KIO3 was required. Calculate the mass fraction of La and Ce in the sample.

mass fraction La:

g Lag sample

mass fraction Ce:

g Ceg sample

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queen_honey_blossom answered 1 month ago

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