A 0.5070 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and...

A 0.5070 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and Ce(NO3)3 (molar mass = 326.13 g/mol) was dissolved in water. The solution was titrated with KIO3, producing the precipitates La(IO3)3 and Ce(IO3)3. For the complete titration of both La3+ and Ce3+, 42.10 mL of 0.1204 M KIO3 was required. Calculate the mass fraction of La and Ce in the sample.

mass fraction La:

g Lag sample

mass fraction Ce:

g Ceg sample

Expert Solution

Hope that this solution will help you.

Kindly upvote it.

queen_honey_blossom answered 9 months ago

A 0.5065 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and...

A 0.5065 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and Ce(NO3)3 (molar mass = 326.13 g/mol) was dissolved in water. The solution was titrated with KIO3, producing the precipitates La(IO3)3(s) and Ce(IO3)3(s). For the complete titration of both La3 and Ce3 , 44.81 mL of 0.1252 M KIO3 was required. Calculate the mass fraction of La and Ce in the sample.

A 0.5072 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and...

A 0.5072 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and Ce(NO3)3 (molar mass = 326.13 g/mol) was dissolved in water. The solution was titrated with KIO3, producing the precipitates La(IO3)3(s) and Ce(IO3)3(s). For the complete titration of both La3 and Ce3 , 44.01 mL of 0.1289 M KIO3 was required. Calculate the mass fraction of La and Ce in the sample.

A 0.5206 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and...

A 0.5206 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and Ce(NO3)3 (molar mass = 326.13 g/mol) was dissolved in water. The solution was titrated with KIO3, producing the precipitates La(IO3)3(s) and Ce(IO3)3(s). For the complete titration of both La3 and Ce3 , 43.38 mL of 0.1236 M KIO3 was required. Calculate the mass fraction of La and Ce in the sample.

a 0.5153g solid sample containing only a mixture of LaCl3 & Ce(NO3)3 was dissolved in water....

a 0.5153g solid sample containing only a mixture of LaCl3 & Ce(NO3)3 was dissolved in water. Potassium iodate was then added to the obtained solution producing the precipitates La(IO3)3 molar mass 663.61 g/mol & Ce(IO3)3 molar mass 664.82 g/mol. the total mass of the precipitates was found to be equal to 1.1650g. Calc the % of LaCl3 and Ce(NO3)3 in the sample. i have to where there are two equations and two unknowns. I just don't know how to solve...

A 0.520 g sample of a diprotic acid with a molar mass of 255.8 g/mol is...

A 0.520 g sample of a diprotic acid with a molar mass of 255.8 g/mol is dissolved in water to a total volume of 23.0 mL . The solution is then titrated with a saturated calcium hydroxide solution. a. Assuming that the pKa values for each ionization step are sufficiently different to see two equivalence points, determine the volume of added base for the first and second equivalence points. b. The pH after adding 23.0 mL of the base was...

A .435 g sample of a nonvolatile, nonionizable solute with a molar mass of 67.4 g/mol...

A .435 g sample of a nonvolatile, nonionizable solute with a molar mass of 67.4 g/mol is dissolved in 15.1 g of cyclohexane. Calculate the molar concentration of solute in the solution. Calculate the boiling point of the solution described. Calculate the freezing point of the solution described.

Chem Question - Gases Molar Mass N = 14.01 g/mol Molar Mass H2O = 18.016 g/mol...

Chem Question - Gases Molar Mass N = 14.01 g/mol Molar Mass H2O = 18.016 g/mol Vapor Pressure of Water at 25 C is 23.76 torr Vapor Pressure of Water at 65 C is 187.54 torr (Show all work and calculations, include units in answer. If calculations must be used in several parts, rounding should be made to 6 decimal points to ensure accuracy. Final Answers can be rounded to 3 decimal points.) A syringe filled with air can be...

A sample weighing 3.027 g is a mixture of Fe2O3 (molar mass = 159.69) and Al2O3...

A sample weighing 3.027 g is a mixture of Fe2O3 (molar mass = 159.69) and Al2O3 (molar mass = 101.96). When heat and a stream of H2 gas is applied to the sample, the Fe2O3 reacts to form metallic Fe and H2O(g). The Al2O3 does not react. If the sample residue (the solid species remaining after the reaction) weighs 2.889 g, what is the mass fraction of Fe2O3 in the original sample?

A sample weighing 3.082 g is a mixture of Fe2O3 (molar mass = 159.69) and Al2O3...

A sample weighing 3.082 g is a mixture of Fe2O3 (molar mass = 159.69) and Al2O3 (molar mass = 101.96). When heat and a stream of H2 gas is applied to the sample, the Fe2O3 reacts to form metallic Fe and H2O(g). The Al2O3 does not react. If the sample residue (the solid species remaining after the reaction) weighs 2.637 g, what is the mass fraction of Fe2O3 in the original sample?

A 0.1276−g sample of a monoprotic acid (molar mass = 1.10 × 102 g/mol) was dissolved...

A 0.1276−g sample of a monoprotic acid (molar mass = 1.10 × 102 g/mol) was dissolved in 25.0 mL of water and titrated with 0.0633 M NaOH. After 10.0 mL of base had been added, the pH was determined to be 4.87. What is the Ka for the acid? Answer in scientific notation.

Question