In: Computer Science
Show using a direct proof and logical operators the following set equality.A−BC= A∩B
Let us consider, for every x we have, x A B
So, x does not belong in BC as it is in B and x A
So, for every value of x, we have x A - BC
So, from this we can say that, A B will be subset of A - BC
Let us consider, for every y we have, y A - BC
So, y does not belong in BC as it is in B and y A
Also, y B.
So, for every y A B
So, from this we can say that, A - BC will be subset of A B
So, we can say that A B = A - BC (proved)
Please comment in case of any doubt.
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