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Mining companies use this reaction to obtain iron from iron ore : Fe2O3(s) + 3CO(g) =...

Mining companies use this reaction to obtain iron from iron ore : Fe2O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g). The reaction of 167g Fe2O3 with 84.7g CO produces 76.5g Fe. Determine the theoretical yield. Determine the percent yield.

Solutions

Expert Solution

                Fe2O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g)

no of moles of Fe2O3 = W/G.M.Wt

                                     = 167/160 = 1.044 moles

no of moles of CO    = W/G.M.Wt

                                 = 84.7/28 = 3.025 moles

1mole of Fe2O3 react with 3 moles of CO

1.044 moles of Fe2O3 react with = 3*1.044 = 3.132 moles of CO

   CO is limiting reagent

3 moles of CO react with Fe2O3 to gives 2 moles of Fe

3.025 moles of CO react with Fe2O3 to gives = 2*3.025/3    = 2.016 moles of Fe

mass of Fe = no of moles * G. A.Wt

                   = 2.016*56   = 112.89g of Fe

percentage yield   = actual yield*100/theoretical yield

                              = 76.5*100/112.89   = 67.76%

queen_honey_blossom answered 1 year ago
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