In: Chemistry
Iron(III) oxide reacts with carbon monoxide according to the
equation:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
A reaction mixture initially contains 23.00 g Fe2O3 and 16.00 g
CO.
Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left?
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Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
no of moles of Fe2O3 = W/G.M.Wt
= 23/159.69 = 0.144 moles
no of moles of CO = W/G.M.Wt
= 16/28 =0.57 moles
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
1 mole of Fe2O3 react with 3 moles of CO
0.144 moles of Fe2O3 react with = 3*0.144/1 = 0.432 moles of CO
CO is excess reactant
The no of moles of excess reactant left after complete the reaction = 0.57-0.432 = 0.138 moles
The amount of excess reactant left after complete the reaction = no of moles * gram molar mass
= 0.138*28 = 3.864g of CO >>answer