Question

A particular fruit's weights are normally distributed, with a mean of 455 grams and a standard deviation of 5 grams.

If you pick one fruit at random, what is the probability that it will weigh between 459 grams and 465 grams

Answer 1

Solution :

Given that ,

mean =   = 455

standard deviation = = 5   

n = 1

= 455

=  / n= 5 / 1=5

P(459<     < 465) = P[(459-455) / 5< ( - ) /   < (465-455) / 5)]

= P( 0.8< Z < 2)

= P(Z < 2) - P(Z <0.8 )

Using z table

=0.9772-0.7881

=0.1891

probability=0.1891