Question

A particular fruit's weights are normally distributed, with a mean of 679 grams and a standard deviation of 29 grams.

If you pick one fruit at random, what is the probability that it will weigh between 668 grams and 713 grams

Answer 1

Solution :

Given that ,

mean =   = 679

standard deviation = = 29

n = 1

= 679

=  / n= 29 / 1=29

P(668<     <713 ) = P[(668-679) /29 < ( - ) /   < (713-679) / 29)]

= P( -0.38< Z <1.17 )

= P(Z < 1.17) - P(Z <-0.38 )

Using z table

=0.8790-0.3520

=0.5270

probability= 0.5270