In: Chemistry
For a solution equimolar in HCN and NaCN, which statement is false?
A. |
[H+] is larger than it would be if only the HCN were in solution. |
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B. |
Addition of NaOH will increase [CN–] and decrease [HCN]. |
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C. |
[H+] is equal to Ka. |
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D. |
This is an example of the common-ion effect. |
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E. |
Addition of more NaCN will shift the acid-dissociation equilibrium of HCN to the left. |
Answer is
[H+] is equal to Ka this statement is false
regarding common ion effect all other state ments are correct
Ka is the percentage of the dissociation of H+ which will depend on concentration of HCN whic was not equal to H+