Question

The Panama City Times recently conducted a survey of local high school juniors and seniors and found that 59.8% of them planned on attending Gulf Coast State College within the next 2 years. If 12 local high school students are selected randomly from this area, what the probability that fewer than 4 of them will say they plan on attending GCSC within the next 2 years?

what would my n, x and p be? using the calculator( binomcdf)

Answer 1

The probability that a randomly selected high school student planned on attending Gulf Coast State College within the next 2 years is 0.598

Let X be the number of students out of 12 who will say they plan on attending GCSC within the next 2 years. We can say that X has a Binomial distribution with parameters, number of trials (number of students selected) n=12, success probability ( The probability that a randomly selected high school student planned on attending Gulf Coast State College within the next 2 years) p=0.598

The Binomial probability of X=x students out of 12, will say they plan on attending GCSC within the next 2 years is given by

The probability that fewer than 4 of them (3 or less) will say they plan on attending GCSC within the next 2 years is

, which is same as

Using TI-83 function binomcdf(n,p,x) we can get P(X<=3) as binomcdf(12,0.598,3)

steps:

press 2nd+VARS and pick binomcdf under DISTR

Enter

binomcdf(12,0.598,3) to get

ans: The probability that fewer than 4 of them will say they plan on attending GCSC within the next 2 years is 0.0158