In: Statistics and Probability
A researcher was interested in investigating if younger women feel more positively toward themselves than older women. She obtains the cooperation of five mother-daughter pairs. The daughters are all college students. She then administers a measure of self-esteem to these ten women. The scores range from zero to ten with ten meaning high self-esteem. The scores are as follows:
Mother-Daughter Pair |
Mother |
Daughter |
1 |
4 |
6 |
2 |
10 |
10 |
3 |
6 |
8 |
4 |
9 |
7 |
5 |
6 |
9 |
1. State the null and research hypotheses.
2. Find the Critical Value using the T-Table and interpret what you will do with the null hypothesis given that Critical Value
3. Identify the Correct Degrees of Freedom you’ll use in the table
4. Calculate the t-value. Show your work. Start with the formula and then plug in the correct values from there.
5. Make a decision regarding the null. Interpret your decision with regard to this question.
6. Calculate the effect size and interpret what it means.
7. Construct a 95% Confidence Interval for the difference between the two groups.
8. Reflect on the results and the exercise (summarize the results).
(1)
H0: Null Hypothesis:
HA: Alternative Hypothesis:
(2)
= 0.05
ndf = n - 1 = 5 - 1= 4
One Tail Left Side Test
From Table, critical value of t = - 2.1318
Decision Rule:
Reject null hypothesis: if t < - 2.1318
(3)
Degrees of freedom is given by:
ndf = n - 1 = 5 - 1= 4
(4)
From the given data,values of d = Mother - Daughter are got as follows:
d = - 2, 0, - 2, 2, - 3
From d values,the following statistics are calculated:
n = 5
= -5/5 = - 1
sd = 2
SE = sd/
= 2/
=0.8944
Test statistic is given by:
t = /SE
= - 1/0.8944
= - 1.1180
(5)
Since calculated value of t = - 1.1180 is greater than critical value of t = - 2.1318, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data do not support the claim that younger women feel more positively toward themselves than older women.
(6)
Effect size : Cohen's d for Dependent Samples t test:
From the given data, the following statistics are calculated:
m1= 7
s1 = 2.4495
m2 = 8
s2 = 1.5811
r = 0.5809
Substituting values, we get:
So,
Effect size = 0.500
Interpretation:
Since Effect size = 0.5, the effect is medium.
(7)
ndf =4
=0.05
From Table,
critical values of t = 2.7764
Confidence interval:
- 1 (2.7764 X 0.8944)
= - 1 2.4832
= ( - 3.4832,1.4832)
Confidence Interval:
- 3.4832 < < 1.4832
(8)
Since the confidence interval contains 0, we conclude:
The data do not support the claim that younger women feel more positively toward themselves than older women.