The average electricity usage per month for a 2000 ft2 house is 550 kWh and the...

The average electricity usage per month for a 2000 ft² house is 550 kWh and the standard deviation is 180 kWh.

What is the probability that a household will use more than 750 kWh per month?

It might help to sketch the distribution and put the important information on the graph.

z=? p(x>750)=?

Expert Solution

Let x be the electricity usage per month.

x follows normal distribution with with mean ( µ ) = 550 kWh and standard deviation (σ) = 180 kWh

P(x>750)

z =

z = 1.11

Area less than z = 1.11 on z score is 0.8665

Therefore area greater than 1.11 is 1 - 0.8665 = 0.1335

P(x>750) = 0.1335

orchestra answered 1 year ago

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