Question

In: Statistics and Probability

A 2010 study asserts that the number of hours that the average college student studies each...

A 2010 study asserts that the number of hours that the average college student studies each week has been steadily dropping (The Boston Globe, July 4, 2010). In fact, the researchers state that, in the U.S., today’s undergraduates study an average of 14 hours per week. Suppose an administrator at a local university wants to show that the average study time of students at his university differs from the national average. He takes a random sample of 35 students at is university and finds that the average number of hours spent studying per week is 16.3. Assume that the population standard deviation is 7.2 hours. At 0.05 level of significance, what is the test statistics for testing the hypotheses H0: µ = 14 versus H1: µ ≠ 14?

Solutions

Expert Solution

Solution :

= 16.3

=14

=72

n = 35

This is the two tailed test .

The null and alternative hypothesis is ,

H0 :    = 14

Ha :     14

Test statistic = z

= ( - ) / / n

= (16.3 - 14) / 7.2 / 35

= 1.89

Test statistic = z = 1.89

P(z > 1.89 ) = 1 - P(z < 1.89 ) = 1 - 0.9706

P-value = 2 * 0.0294 = 0.0588

= 0.05  

P-value >

0.0588 > 0.05

Fail to reject the null hypothesis .

There is insufficient evidence to suggest that


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