Question

Translate the following C program to Pep/9 assembly language.

#include <stdio.h.>

int main() {

int numitms,j,data,sum;

scanf("%d", &numitms);

sum=0;

for (j=1;j<=numitms;j++) {

scanf("%d", &data);

sum+=data;

}

printf("sum: %d\n",sum);

return0;

}

I got an answer with an error. Please debug the answer or have a new correct answer (don't copy and paste others' answer)

main: SUBSP 2,i
DECI numItms,i
DECI j,j
DECI data,d
DECI sum,s
LDWA numItms,i
sum: .EQUATE 0
LDWA 1,i
STWA j,j
for: CPWA numItms, j
BRGE endFor
STRO msg,d
DECO j,s
LDBA '\n',i
STBA charOut,d
LDWA j,s ;j++)
ADDA 1,i
STWA j,s
BR for
endFor: ADDSP 2,i ; STOP
msg: .ASCII "Sum = \x00"
.END

Answer 1

main:
        push    {r11, lr}
        mov     r11, sp
        sub     sp, sp, #16
        ldr     r0, .LCPI0_0
.LPC0_0:
        add     r0, pc, r0
        sub     r1, r11, #4
        bl      __isoc99_scanf
        movw    r1, #0
        str     r1, [sp]
        movw    r1, #1
        str     r1, [sp, #8]
.LBB0_1:                                @ =>This Inner Loop Header: Depth=1
        ldr     r0, [sp, #8]
        ldr     r1, [r11, #-4]
        cmp     r0, r1
        bgt     .LBB0_4
        ldr     r0, .LCPI0_2
.LPC0_2:
        add     r0, pc, r0
        add     r1, sp, #4
        bl      __isoc99_scanf
        ldr     r1, [sp, #4]
        ldr     r2, [sp]
        add     r1, r2, r1
        str     r1, [sp]
        ldr     r0, [sp, #8]
        add     r0, r0, #1
        str     r0, [sp, #8]
        b       .LBB0_1
.LBB0_4:
        ldr     r0, .LCPI0_1
.LPC0_1:
        add     r0, pc, r0
        ldr     r1, [sp]
        bl      printf
        mov     sp, r11
        pop     {r11, pc}
.LCPI0_0:
        .long   .L.str-(.LPC0_0+8)
.LCPI0_1:
        .long   .L.str.1-(.LPC0_1+8)
.LCPI0_2:
        .long   .L.str-(.LPC0_2+8)
.L.str:
        .asciz "%d"

.L.str.1:
        .asciz "sum: %d\n"