Question

Translate the following C program to PEP/9 assembly language.

#include <stdio.h>

Int main (){

int number;

Scanf (“%d”, & number);

if (number % 2 ==0) {

printf (“Even\n”);

}

else {

printf(“Odd\n”);

}

Return 0;

}

Answer 1

Step(1)

The Pep/9 Computer Simulation (also known as Pep9) is a virtual machine that is used by professors of schools and colleges to explain and simplify the lowest level of computing.

The Pep/9 is a direct descendant of the Pep/6 virtual machine, the only major difference is that it has been expanded from 4KiB to 32KiB of system RAM. The machine code format remains the same.

Step(2)

The gcc provides a great feature to get all intermediate outputs from a source code while executing. To get the assembler output we can use the option ‘-S’ for the gcc. This option shows the output after compiling, but before sending to the assembler. The syntax of this command is like below.

gcc –S program.c

Step(3)

CODE-

BR       main

number: .EQUATE    int number ;local variable #2d

main :

            SUBSP 2,i ;push #number

           DECI number,s ;scanf("%d", &number) (get number)

           LDWA number,s ; if (number %2 == 0) (check if number %2 is zero)

           BRGE elseIf

          STRO print1,d ;printf("Even\n")

BR     endIf

elseif:

          STRO print2 , d ;printf("Odd\n")

endIf:

ADDSP 2,i    

          STOP

print1 :      .

          .ASCII "Even\n\x00"

Print1:

    .ASCII "Odd\n\x00"

.END

IF YOU HAVE ANY DOUBT PLEASE COMMENT DOWN BELOW I WILL SOLVE IT FOR YOU:)
----------------PLEASE RATE THE ANSWER-----------THANK YOU!!!!!!!!----------