Question

In: Chemistry

A solution of HCN(aq) is made. When the solution comes to equilibrium, which of the following...

A solution of HCN(aq) is made. When the solution comes to equilibrium, which of the following is true? HCN(aq) ⇌ ⇌ H+(aq) + CN–(aq) with Kc = 7.9 x 10–10 A. The reaction mixture will contain mostly HCN. B. The reaction mixture will contain comparable amounts of HCN, H+, and CN- C. The reaction mixture will contain mostly H+ and CN-.

Solutions

Expert Solution

Correct answer is (A)

According to Le Chateriels principle, more the concentration of reactants, more reactions favors towards products.

In the given reaction, reaction is more more towards to products H+ & CN- so option A is correct.


Related Solutions

Hydrocyanic acid will set up the following equilibrium when dissolved in water: HCN(aq) + H2O(l) <-->...
Hydrocyanic acid will set up the following equilibrium when dissolved in water: HCN(aq) + H2O(l) <--> CN-(aq) +H3O+(aq) a) calculate the pH of a .123 M solution of hydrocyanic acid ANSWER: pH = 5.01 b) To 500mL of the solution in part (a) is added 5.00g of solid NaCN. Calculate the pH of new solution. Assume no volume change has occured. c) If one were to add 10.00mL of a .100M NaOH solution to the solution prepared in part (b),...
What is the equilibrium constant expression for the following reaction: HCN(aq) + H2O(l)↔CN−(aq) + H3O+(aq) Choose...
What is the equilibrium constant expression for the following reaction: HCN(aq) + H2O(l)↔CN−(aq) + H3O+(aq) Choose from the list below and enter the letters alphabetical order. (e.g. For an equilibrium constant of [H3O+]-1eq[HCN]eq enter AH.) A) [HCN]eq E) [HCN]-1eq I) [Ru(NH3)62+]6eq B) [H2O]eq F) [H2O]-1eq J) [Ru2+]-6eq C) [CN-]eq G) [CN-]-1eq K) [NH3]-6eq D) [H3O+]eq H) [H3O+]-1eq L) [Ru(NH3)62+]-6eq
Consider the following dissociation of the weak acid, HCN: HCN(aq) ⇌ CN−(aq) + H+(aq) K =...
Consider the following dissociation of the weak acid, HCN: HCN(aq) ⇌ CN−(aq) + H+(aq) K = 6.2×10-10 A solution is made with an initial concentration of 2.60 M HCN. At equilibrium, what is the concentration of H+ ions in solution? (Hint: You may use the 5% approximation.) ?M
In the following reaction, which reactant is a Brønsted-Lowry acid? NaHS(aq) + HCN(aq) → NaCN(aq) +...
In the following reaction, which reactant is a Brønsted-Lowry acid? NaHS(aq) + HCN(aq) → NaCN(aq) + H2S(aq)
CN-(aq)+NH4(aq) <-> HCN(aq) + NH3(aq) A solution is prepaired with all reactants at 0.45M and all...
CN-(aq)+NH4(aq) <-> HCN(aq) + NH3(aq) A solution is prepaired with all reactants at 0.45M and all products at 0.25M a) Calculate (delta)Go and K (at 298K) b) Calculate Q and G and indicates in what direction the reaction will proceed c) Determine the concentrations once equilbrium is reached d) What would be the effect of heating the solution at equilbrium.
the following equilibrium of a cobalt ion in solution: Co(H2O)62+ (aq) + 4 Cl− (aq) ⇌...
the following equilibrium of a cobalt ion in solution: Co(H2O)62+ (aq) + 4 Cl− (aq) ⇌ CoCl42- (aq) + 6 H2O (l) A. Both an ice bath and a boiling water bath were prepared for use in the following steps. B. In a test tube ~1 mL of Co2+ solution was added followed by drops of 12M HCl until a color change was the seen. C. What is happening at the molecular level as HCl is added to the solution?...
What are the products of the following reaction? HCN(aq) + CH3NH2(aq) → a CH3NH−(aq) + H2CN+(aq)...
What are the products of the following reaction? HCN(aq) + CH3NH2(aq) → a CH3NH−(aq) + H2CN+(aq) + H2O(l) b CH3NH3+(aq) + H2O(l) c NaCN(aq) + H2O(l) d CH3NH3CN(aq)
Consider the reaction HCN(aq) H+(aq) +CN-(aq). the equilibrium constant is 6.2*10^-10. If you place 0.4 mols...
Consider the reaction HCN(aq) H+(aq) +CN-(aq). the equilibrium constant is 6.2*10^-10. If you place 0.4 mols of HCN in a 2.0 liter flask, what is the equilbrium of CN-? so far ive got to x=x(0.2)(6.2*10^-10)
Calculate the value of K in the following reaction: HCN (aq) + F- (aq) <-------> CN-...
Calculate the value of K in the following reaction: HCN (aq) + F- (aq) <-------> CN- (aq) + HF (aq) Ka for HCN = 6.2 x 10^-10 Ka for HF = 7.2 x 10^-4
The three reactions below are all at equilibrium simultaneously in solution. Ca2+ (aq) + C2O42- (aq)...
The three reactions below are all at equilibrium simultaneously in solution. Ca2+ (aq) + C2O42- (aq) « CaC2O4 (s) H2C2O4(aq)«H+(aq)+HC2O4-(aq) HC2O4- (aq) « H + (aq) + C2O42- (aq) a. If HNO3 is added to this solution, would you expect to see more or less of the precipitate (CaC2O4) formed in the solution? Explain your reasoning by showing the effect of the addition of HNO3 on the equilibrium for the reaction.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT