In: Statistics and Probability
You may need to use the appropriate technology to answer this question.
Develop the analysis of variance computations for the following completely randomized design. At α = 0.05, is there a significant difference between the treatment means?
Treatment | |||
---|---|---|---|
A | B | C | |
137 | 106 | 92 | |
120 | 115 | 83 | |
113 | 124 | 84 | |
106 | 104 | 102 | |
130 | 108 | 89 | |
114 | 110 | 117 | |
130 | 97 | 111 | |
102 | 113 | 119 | |
105 | 98 | ||
88 | 105 | ||
xj |
119 | 107 | 100 |
sj2 |
155.14 | 97.11 | 170.44 |
State the null and alternative hypotheses.
H0: μA =
μB = μC
Ha: Not all the population means are
equal.H0: At least two of the population means
are equal.
Ha: At least two of the population means are
different. H0:
μA = μB =
μC
Ha: μA ≠
μB ≠
μCH0:
μA ≠ μB ≠
μC
Ha: μA =
μB =
μCH0: Not all the
population means are equal.
Ha: μA =
μB = μC
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.Reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal. Do not reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal.Do not reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
The statistical software output for this problem is:
Hence,
Hypotheses:
H0: μA =
μB = μC
Ha: Not all the population means are equal.
Test statistic = 5.79
P - value = 0.0086
Conclusion: Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.