In: Statistics and Probability
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an estimate at the 98% level of confidence. For a sample of 4725 third graders, the mean words per minute read was 27.3. Assume a population standard deviation of 6.3. Construct the confidence interval for the mean number of words a third grader can read per minute. Round your answers to one decimal place.
Solution :
Given that,
Point estimate = sample mean =
= 27.3
Population standard deviation =
= 6.3
Sample size = n = 4725
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
Z/2 = Z0.01 = 2.326 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 2.326 * ( 6.3 /
4725 )
= 0.2132
At 98% confidence interval estimate of the population mean
is,
- E <
<
+ E
27.3 - 0.2132 <
< 27.3 + 0.2132
27.0868 <
< 27.5132
( 27.1 , 27.5)