In: Statistics and Probability
Carbon monoxide emissions for a particular car vary with an average of 2.5 g/mi and a standard deviation of 0.3 g/mi. A company has 60 of these cars in its fleet. If X= the CO level for the company's fleet, what is the probability that the average of the 60 cars falls between 2.55 and 2.6 g/mi? Round your answer to four decimal places .
Solution :
Given that ,
mean = = 2.5
standard deviation = = 0.3
n = 60
= 2.5
= / n= 0.3 / 60=0.03873
P(2.55< <2.6 ) = P[(2.55-2.5) / 0.03873 < ( - ) / < (2.6-2.5) /0.03873 )]
= P( 1.29< Z <2.58 )
= P(Z <2.58 ) - P(Z <1.29 )
Using z table
=0.9951-0.9015
=0.0936
probabilty=0.0936