Carbon monoxide emissions for a particular car vary with an average of 2.5 g/mi and a...

Carbon monoxide emissions for a particular car vary with an average of 2.5 g/mi and a standard deviation of 0.3 g/mi. A company has 60 of these cars in its fleet. If X= the CO level for the company's fleet, what is the probability that the average of the 60 cars falls between 2.55 and 2.6 g/mi? Round your answer to four decimal places .

Solutions

Expert Solution

Solution :

Given that ,

mean = = 2.5

standard deviation = = 0.3

n = 60

= 2.5

= / $\sqrt$ n= 0.3 / $\sqrt$ 60=0.03873

P(2.55< <2.6 ) = P[(2.55-2.5) / 0.03873 < ( - ) / < (2.6-2.5) /0.03873 )]

= P( 1.29< Z <2.58 )

= P(Z <2.58 ) - P(Z <1.29 )

Using z table

=0.9951-0.9015

=0.0936

probabilty=0.0936

orchestra answered 2 years ago

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