Question

In: Statistics and Probability

Researchers used a standard fish seine to sample the fish population of Mason Pond. Most of...

Researchers used a standard fish seine to sample the fish population of Mason Pond. Most of these fish were bluegill (Lepomis macrochirus). Researchers removed fish from the seine and measured these fish on a fish board the boat. Researchers measured each fish to the nearest millimeter. Then, researchers measured all of the fish brought in by your seine, except for fish less than 15 mm.   

Size Category

Observed

Expected

15-35 mm

22

7.33

>35-55 mm

16

5.33

>55 mm

6

2

  1. As indicated above, test the null hypothesis that the fish size classes are evenly distributed using a chi-square analysis. Did our seine sample adequately test the fish population for the entire pond? Why or why not? If fish sizes are not evenly distributed, what ecological factors could explain this uneven distribution?

Solutions

Expert Solution

We are given the following data and are asked to test the hypothesis that the fish size classes are evenly distributed using a chi-square analysis.

Size Category Observed Expected
15-35mm 22 7.33
>35-55mm 16 5.33
>55mm 6 2

Null hypothesis

H0: fish size classes are evenly distributed

Alternate hypothesis

H1: fish size classes are not evenly distributed.

Test statistic under H0:

Size Category Observed Expected Observed-Expected (Observed-Expected)2/Expected
15-35mm 22 7.33 14.67 29.36
>35-55mm 16 5.33 10.67 21.36
>55mm 6 2 4 8

Inference

at 5% level of significance and at 4 d.f. from tables

, null hypothesis may be rejected.

Hence we conclude that the fish size classes are not evenly distributed i.e., our seine sample did not adequately test the fish population for the entire pond.

One of the ecological factors could be overfishing for fishes who have the largest size. Another factor could be trophy hunting i.e., hunting fishes which have the largest size and weight.


Related Solutions

Assume there is a certain population of fish in a pond whose growth is described by...
Assume there is a certain population of fish in a pond whose growth is described by the logistic equation. It is estimated that the carrying capacity for the pond is 1000 fish. Absent constraints, the population would grow by 240% per year. If the starting population is given by p 0 = 600 , then after one breeding season the population of the pond is given by p 1 = After two breeding seasons the population of the pond is...
Researchers investigating cave fish found a new population in a previously undiscovered cave. These fish also...
Researchers investigating cave fish found a new population in a previously undiscovered cave. These fish also lacked eyes, but different from the other populations, their eye development appeared to fail during lens induction. The researchers observed a failure to induce a lens placode. Their next goal was to determine the mechanism that caused loss of eyes in this population. a) (2 points) The researchers hypothesized that a loss of function mutation in one or more of six possible genes was...
Fish Ventilation Most fish use gills for respiration in water and researchers can observe how fast...
Fish Ventilation Most fish use gills for respiration in water and researchers can observe how fast a fish’s gill cover beats to study ventilation, much like we might observe breathing rate for a person. Professor Brad Baldwin is interested in how water chemistry might affect gill beat rates. In one experiment he randomly assigned fish to tanks with different levels of calcium. One tank was low in calcium (0.71 mg/L), the second tank had a medium amount (5.24 mg/L), and...
IST analyzes the fish population of coastal alaska waters. each year they sample 100 fish and...
IST analyzes the fish population of coastal alaska waters. each year they sample 100 fish and measure their weight. the table shows the mean fish weights for 2016, 2017, 2018. Assume a population standard deviation of 5lb. alpha = .05 Year. Mean salmon weight lb 2016: 18 2017: 19 2018: 23 A.) is the increase from 2016 to 2017 statistically significant. state test statistic and p-value, then answer the question. B) is the increase from 2017 to 2018 statistically significant....
A particular fish population has a mean length of 230 mm and a standard deviation of...
A particular fish population has a mean length of 230 mm and a standard deviation of 50 mm. What is the probability that a random sample of 16 fish from this population has a mean length of at least 240 mm?
Item Sample Mean 1 Population standard deviation of 1 n1 Sample Mean 2 Population Standard Deviation...
Item Sample Mean 1 Population standard deviation of 1 n1 Sample Mean 2 Population Standard Deviation 2 n2 7 18 6 169 12 12 121 0.01 Perform a Two-tailed hypothesis test for two population means.
A sample of 260 observations is selected from a normal population with a population standard deviation...
A sample of 260 observations is selected from a normal population with a population standard deviation of 26. The sample mean is 15. Determine the standard error of the mean. Determine the 98% confidence interval for the population mean. (Use z Distribution Table.) (Round your answers to 3 decimal places.)
A sample of 44 observations is selected from one population with a population standard deviation of...
A sample of 44 observations is selected from one population with a population standard deviation of 3.1. The sample mean is 101.0. A sample of 56 observations is selected from a second population with a population standard deviation of 5.0. The sample mean is 99.5. Conduct the following test of hypothesis using the 0.10 significance level. H0:U1=U2 H1: U1 does not equal U2 a. is this a one or two tailed test? b.state the decision rule rounded 2 decimals the...
a sample of 245 observations is selected from a normal population for which the population standard...
a sample of 245 observations is selected from a normal population for which the population standard deviation is known to be 25. the sample mean is 20. determine the standard error of the mean. determine the 90% confidence interval for the population mean.
A sample of 65 observations is selected from one population with a population standard deviation of...
A sample of 65 observations is selected from one population with a population standard deviation of 0.75. The sample mean is 2.67. A sample of 50 observations is selected from a second population with a population standard deviation of 0.66. The sample mean is 2.59/ conduct the following test of hypothesis using the 0.08 significance level: Ho: m1 £ m2     H1: m1 > m2 Is this a one-tailed or a tow-tailed test? State the decision rule. Compute the value of...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT