Question

A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 16 16 nursing students from Group 1 resulted in a mean score of 55.4 55.4 with a standard deviation of 4.5 4.5 . A random sample of 8 8 nursing students from Group 2 resulted in a mean score of 66 66 with a standard deviation of 8.3 8.3 . Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1 μ 1 represent the mean score for Group 1 and μ2 μ 2 represent the mean score for Group 2. Use a significance level of α=0.05 α = 0.05 for the test. Assume that the population variances are equal and that the two populations are normally distributed.

Step 1 of 4 : State the null and alternative hypotheses for the test. Step 2 of 4: Compute the value of the t test statistic. Round your answer to three decimal places. Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round your answer to three decimal places. Step 4 of 4: State the test's conclusion.

Answer 1

Here, we conduct the T-test for two means as :

Hence, we conclude that mean score for Group 1 is significantly lower than the mean score for Group 2 at 5% level of significance.