Question

In: Biology

If a colorblind man marries a normal vision woman and have color blind daughter. What is...

If a colorblind man marries a normal vision woman and have color blind daughter. What is the probability that their next child will be color blind? What is the probablity that their next child will have normal vision?

Expert Solution

Solution

Comon type of red-green color blindness is an X linked recessive trait

Remember males are XY and Females are XX sex chromosomes

Possible genotype of colourblind man = XCY (XC represent defective gene)

Possible genotype of mother = XCX (mother do dot have colourblindness but she is a carrier)

Possible genotype of their daughter who is colour blind is XCXC . Because for a female to become colour blind, she should have two defective X chromosome (remember color blindness is an X linked recessive trait)

Look at the following Punnet square

Where,

XXC is carrier female

XCXC is colour blind female

XCY is colour blind male

XY is normal male

From the above punnet square the following conclusions can be made

The probability that their next child (either male or female) is colourblind is (2/4)* 100 = 50% or 1/2

The probability that their next child (either male or female) is normal is (2/4)* 100 = 50% or 1/2

gladiator answered 2 years ago

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