In: Biology
A normal man marries an affected woman with an X-linked recessive disease. The expected genotypes of their offspring are_________.
In an X- linked disease, the abnormal alelle is present at the X-chromosome. Since it is recessive, both the alleles of that particular gene has to be affected for the disease to be manifested.
Let the abnormal allele be represented by x'. And X is the normal allele.
We know, the chromosome pattern in a male is XY and female is XX.
Since females have 2 copies of the X chromosomes, both the alleles should be affected (x') for the disease to be manifested. Females with one affected allele will be carriers.
XX - Normal female;... x'x' - Affected female;...Xx' - Carrier female
Whereas, males have a single X chromosome. When this is affected (x') the disease is manifested. So, there is no carrier state in males.
XY - Normal male;... x'Y - Affected male;...No carrier male
-------------------------------------------------------------------------------------------------------------
Here, cross is between a normal man (XY) and an affected woman (x'x')
The gametes will be :
The Punnet square is :
x | X | Y |
x' | Xx' | x'Y |
x' | Xx' | x'Y |
The genotypes of the offsprings will be 2 / 4 Xx' : 2 / 4 x'Y
i.e 50 % Xx' : 50 % x'Y
So, All the female offsprings will be carriers (Xx') and all the male offsprings will be affected (x'Y).