If a phenotypically normal woman whose father suffered from hemophilia marries a normal man, what is...

If a phenotypically normal woman whose father suffered from hemophilia marries a normal man, what is the probability of hemophilia occurring in the children produced by this marriage? (Show the cross and give the genetic ratios by sex.) In the next case, assume that the same woman had a husband with a genotypically homozygous normal mother but whose father also had hemophilia. What will then be the chance of hemophilia in the children? Give genotypic and phenotypic ratios for the children by sex. This is an X-linked cross.

Expert Solution

Case I. Woman is normal with haemophilic father. A female gets one X chromosome from mother and one X chromosome from father. It means that the woman gets normal X chromosome from mother but haemophilic X chromosome from father. Hence she is a carrier with genotype XXh . She marries a normal man so the genotype of man would be XY. The cross gives following results

The probability of haemophilic children is 0.25

No females will be haemophilic while the probability of haemophilic male will be 0.50

Case II. Women is same so her genotype is XXh. Her husband had genetically normal mother but haemophilic father. So husband gets normal X chromosome from his mother and Y chromosome from his mother. So the genotype of husband will be XY.

The results of cross will be same as case I.

gladiator answered 2 years ago

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