In: Statistics and Probability
If np ≥5 and nq ≥5, estimate P (at least 7) with n =13 and p=0.6 by using the normal distribution as an approximation to the binomial distribution; if np <5 or nq <5, then state that the normal approximation is not suitable.
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
P (at least 7) =
(Round to three decimal places as needed.)
B.
The normal distribution cannot be used.
Solution:
Given that,
P = 0.6
1 - P = 0.4
n = 13
Here, BIN ( n , P ) that is , BIN (13 , 0.6)
then,
n*p = 7.8 5
n(1- P) = 5.2 5
According to normal approximation binomial,
X Normal
Mean = = n*P = 7.8
Standard deviation = =n*p*(1-p) = 3.12
We using continuity correction factor
A)
P(X a ) = P(X > a - 0.5)
P(x > 6.5) = 1 - P(x < 6.5)
= 1 - P((x - ) / < (6.5 - 7.8) / 3.12 )
= 1 - P(z < -0.74)
= 1 - 0.2296 ( using z-table)
= 0.7704
Probability = 0.7704