Question

what volume of 0.200 m HCl solution is needed to neutralize 0.400 g of NaHCO3

Answer 1

To answer this question we will need the reaction equation

HCl is an acid while NaHCO3 is a base and hence reaction between them is an acid-base reaction and the product formed is a salt.

reaction equation

HCl(aq) + NaHCO₃(s) → NaCl(aq) + H₂O(l) + CO₂(g)

here we see that 1 mole HCl is needed to neutralize 1 mole NaHCO₃

or1 mole HCl is needed to neutralize 84g NaHCO₃ (mass NaHCO₃= 1 mole NaHCO₃ x molar mass of NaHCO₃)

for 0.4g of NaHCO₃ ---- 1/84 x 0.4 = 0.004762 moles of HCl needed

moles of HCl = molarity x volume in Litres

0.004762 moles = 0.2 M(or moles/L) x V

V = 0.004762/.2 L = 0.0238 L

or 23.8 mL