In: Chemistry
What volume of 0.115 M HClO4 solution is needed to neutralize 41.00mL of 9.00
NaOH + HClO4 = NaClO4 + H2O
1 mole 1mole
Acid Base
M1 = 0.115M M2 =0.09M
V1 = V2 =41ml
n1 = 1 n1 =1
M1V1 M2V2
n1 n1
0.115*V1/1 = 0.09*41/1
v1 = 32ml