In: Biology
Place the following steps of TRANSLATION in the correct order for EUKARYOTES.
The ribosome reaches a stop codon. A release factor binds and causes the release of the new polypeptide, along with the mRNA. The ribosome dissociates.
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The ribosome moves exactly 3 nucleotides toward the 3' end of the mRNA.
The small ribosomal subunit binds the mRNA near the 5' end and begins to search for the start codon.
A charged tRNA with a matching anticodon binds the mRNA codon in the A site.
The initiator tRNA binds to the small ribosomal subunit.
The ribosome catalyzes the formation of a peptide bond between the amino acids held by the tRNA in the P site and the new amino acid on the charged tRNA in the A site. This tRNA ends up holding the whole chain of amino acids.
The small ribosomal subunit uses rRNA to bind to the Kozak sequence, which places the initiator tRNA on the start codon and in the P site.
The large ribosomal subunit joins the small subunit, ending the
Initiation phase.
Steps involve in the translation are
1.The small ribosomal subunit binds the mRNA near the 5' end and begins to search for the start codon.
2. The small ribosomal subunit uses rRNA to bind to the Kozak sequence, which places the initiator tRNA on the start codon and in the P site.
3.The large ribosomal subunit joins the small subunit, ending the Initiation phase
4.A charged tRNA with a matching anticodon binds the mRNA codon in the A site.The initiator tRNA binds to the small ribosomal subunit.
5.The ribosome catalyzes the formation of a peptide bond between the amino acids held by the tRNA in the P site and the new amino acid on the charged tRNA in the A site. This tRNA ends up holding the whole chain of amino acids.
6.The ribosome moves exactly 3 nucleotides toward the 3' end of the mRNA.
7.The ribosome reaches a stop codon. A release factor binds and causes the release of the new polypeptide, along with the mRNA. The ribosome dissociates.