Question

How many tons of refrigeration is required to cool 50 GPM of liquid from 110 F to 50 F ?

The liquid has a specific heat of 1.40 BTU/lb F and density of 9.2 lb/gal.

Note:

1 Ton refrigeration = 12,000 BTU/hr

Answer 1

Solution

The cooling capacity of the refrigeration expressed in Ton of Refrigeration is to be found out.

Given

Volume flow rate of liquid,

Initial temperature of liquid = 110 ^o F

Final temperature of liquid = 50 ^o F

Density of liquid,

Specific heat of liquid,

Analysis

The cooling capacity of a refrigeration system ie., the rate of heat removed is given by the equation

where, is the mass flow rate of liquid

C is the Specific heat of the liquid

is the temperature change of the liquid

Writing eqn (i) in terms of Volume, we get

since Mass = Density * Volume

Now,

Multipying the above value by 60, we get

To convert the above value in terms of Ton of refrigeration, divide the above value by 12000

(Answer)