The deprotonation of acetic acid goes by the mechanism CH3COOH + H2O ⇒ CH3COO– + H3O+...

The deprotonation of acetic acid goes by the mechanism

CH₃COOH + H₂O ⇒ CH₃COO^– + H₃O⁺

Assume the pKa of acetic acid at 25°C is 4.76, and the forward rate at a pH of 4 is 102 s^–1.

(a) Calculate the forward and reverse rate constants for the reaction.

(b) Calculate the relaxation time if a 10^–2 M solution of solution of acetate in water at pH 6 is subjected to a temperature jump.

(c) Given reasonable estimates for molecular sizes, determine if the forward and/or the reverse reactions are likely to be diffusion limit.

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Expert Solution

queen_honey_blossom answered 1 year ago

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