Question

In: Statistics and Probability

For the following questions you will use StatKey to construct bootstrap confidence intervals for the difference...

For the following questions you will use StatKey to construct bootstrap confidence intervals for the difference in two means. Use the “Home Prices (NY vs NJ)” dataset built into StatKey to address the following.

A. Using the percentile method, construct a 95% confidence interval for the difference in the mean home prices in New York and New Jersey. Take at least 5,000 resamples. Don’t forget to include a screenshot from StatKey and to identify your answer.

B. Using the standard error method, construct a 95% confidence interval for the difference in the mean home prices in New York and New Jersey. You can use the standard error from the bootstrap distribution you constructed in part A. Show all of your work using the equation editor.

C. Explain why the confidence intervals you constructed using the percentile method and the standard error method are not exactly the same. In other words, why may we expect answers in parts A and B to be slightly different?

Solutions

Expert Solution

ANSWER::

(a) The StatKey output is:

The 95% confidence interval is between -445.219 and 85.04.

(b)

-177.13 +- 2.002*132.452

= (-442.261, 88.001)

The 95% confidence interval is between -442.261 and 88.001.

(c)

There is a difference because the standard errors are different for the samples.

NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...

***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU

orchestra answered 1 year ago
Next > < Previous

Related Solutions

Use the following information to construct the confidence intervals specified to estimate μ. a. 95% confidence...
Use the following information to construct the confidence intervals specified to estimate μ. a. 95% confidence for x ¯ = 22, σ = 3.5, and n = 55 b. 98% confidence for x ¯ = 120.6, σ = 28.89, and n = 67 c. 90% confidence for x ¯ = 2.419, σ = 0.888, and n = 29 d. 80% confidence for x ¯ = 56.7, σ = 9.1, N = 500, and n = 47
Use the following information to construct the confidence intervals specified to estimate μ. a. 95% confidence...
Use the following information to construct the confidence intervals specified to estimate μ. a. 95% confidence for = 26, σ = 4.5, and n = 57 b. 98% confidence for = 115.6, σ = 21.89, and n = 79 c. 90% confidence for = 3.419, σ = 0.876, and n = 31 d. 80% confidence for = 55.7, σ = 14.1, N = 500, and n = 43
Activity 4: Confidence interval for a difference in proportions We will use StatKey to calculate a...
Activity 4: Confidence interval for a difference in proportions We will use StatKey to calculate a confidence Interval for a difference in proportions using the StatKey dataset “Use Text Messages (by age)”, which compares text messaging use between teens and adults. 1. Create a bootstrap distribution of 4000 bootstrap differences of proportions using this sample. Use the "Two-tail" option to find the boundaries giving 95% in the middle of the bootstrap distribution. 2. What is the difference in sample proportions...
Using the Excel sheet for Constructing Confidence Intervals, answer the following questions. 1.   Construct a 90%...
Using the Excel sheet for Constructing Confidence Intervals, answer the following questions. 1.   Construct a 90% confidence interval for the true mean of a normal population if a random sample size of 40 from the population yields a sample mean of 75 and the population has a standard deviation of 5. Lower limit: ______________     upper limit: ______________ 2. A random sample, consisting of the values listed below, was taken from a normally distributed population. Assuming the standard deviation of the...
Construct and interpret 95% confidence intervals for the difference in mean pain intensity at 14 days...
Construct and interpret 95% confidence intervals for the difference in mean pain intensity at 14 days after treatment. (Use μVertebroplasty − μPlacebo. Round your answers to two decimal places.) -1.188 Correct: Your answer is correct. to .788 Correct: Your answer is correct. Interpret the interval. There is a 95% chance that the true mean pain intensity 14 days after treatment for the vertebroplasty treatment is directly in the middle of these two values. There is a 95% chance that the...
Use technology to construct the confidence intervals for the proportion variance sigma2 and the population standard...
Use technology to construct the confidence intervals for the proportion variance sigma2 and the population standard deviation sigma. Assume the sample is taken from a normally distributed population. c=0.90, s2=10.89, n=25 The confidence interval for the population variance is (?,?) The confidence interval for the population standard deviation is (?,?)
Use technology to construct the confidence intervals for the population variance sigmasquared and the population standard...
Use technology to construct the confidence intervals for the population variance sigmasquared and the population standard deviation sigma. Assume the sample is taken from a normally distributed population. cequals0.95​, sequals34​, nequals15
Use technology to construct the confidence intervals for the population variance sigmasquared and the population standard...
Use technology to construct the confidence intervals for the population variance sigmasquared and the population standard deviation sigma. Assume the sample is taken from a normally distributed population. c=0.95​, s=39​, n=16
Use technology to construct the confidence intervals for the population variance σ2 and the population standard...
Use technology to construct the confidence intervals for the population variance σ2 and the population standard deviation σ. Assume the sample is taken from a normally distributed population. c=0.90​ s=33​ n=20 The confidence interval for the population variance is (_, _ ) ​(Round to two decimal places as​ needed.) The confidence interval for the population standard deviation is (_, _ ) ​(Round to two decimal places as​ needed.)
Use technology to construct the confidence intervals for the population variance sigma squared and the population...
Use technology to construct the confidence intervals for the population variance sigma squared and the population standard deviation sigma. Assume the sample is taken from a normally distributed population. cequals0.98​, ssquaredequals7.84​, nequals28 The confidence interval for the population variance is
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT