In: Statistics and Probability
A researcher is interested in determining whether typists are most productive in the morning, at midday, in the evening, or late at night. To answer this question, the researcher recruits 20 participants and assigns 5 participants to be measured at each time of day. To evaluate productivity, the researcher measures words typed per minute at each time of day. Answer the following questions considering the data below (alpha = .05)
Morning |
Midday |
Evening |
Night |
|
99 |
42 |
80 |
82 |
|
80 |
32 |
83 |
78 |
|
99 |
45 |
94 |
79 |
|
98 |
49 |
70 |
97 |
|
79 |
38 |
79 |
96 |
|
Mean |
91 |
41.2 |
81.2 |
86.4 |
SStotal = |
9094.95 |
What are the degrees of freedom for the numerator of the F-ratio?
2 |
||
3 |
||
16 |
||
19 |
A researcher is interested in determining whether typists are most productive in the morning, at midday, in the evening, or late at night. To answer this question, the researcher recruits 20 participants and assigns 5 participants to be measured at each time of day. To evaluate productivity, the researcher measures words typed per minute at each time of day. Answer the following questions considering the data below (alpha = .05)
Morning |
Midday |
Evening |
Night |
|
99 |
42 |
80 |
82 |
|
80 |
32 |
83 |
78 |
|
99 |
45 |
94 |
79 |
|
98 |
49 |
70 |
97 |
|
79 |
38 |
79 |
96 |
|
Mean |
91 |
41.2 |
81.2 |
86.4 |
SStotal = |
9094.95 |
What are the degrees of freedom for the denominator of the F-ratio?
2 |
||
3 |
||
16 |
||
19 |
A researcher is interested in determining whether typists are most productive in the morning, at midday, in the evening, or late at night. To answer this question, the researcher recruits 20 participants and assigns 5 participants to be measured at each time of day. To evaluate productivity, the researcher measures words typed per minute at each time of day. Answer the following questions considering the data below (alpha = .05)
Morning |
Midday |
Evening |
Night |
|
99 |
42 |
80 |
82 |
|
80 |
32 |
83 |
78 |
|
99 |
45 |
94 |
79 |
|
98 |
49 |
70 |
97 |
|
79 |
38 |
79 |
96 |
|
Mean |
91 |
41.2 |
81.2 |
86.4 |
SStotal = |
9094.95 |
What is the critical F value for this analysis?
3.24 |
||
4.46 |
||
6.04 |
||
19.00 |
A researcher is interested in determining whether typists are most productive in the morning, at midday, in the evening, or late at night. To answer this question, the researcher recruits 20 participants and assigns 5 participants to be measured at each time of day. To evaluate productivity, the researcher measures words typed per minute at each time of day. Answer the following questions considering the data below (alpha = .05)
Morning |
Midday |
Evening |
Night |
|
99 |
42 |
80 |
82 |
|
80 |
32 |
83 |
78 |
|
99 |
45 |
94 |
79 |
|
98 |
49 |
70 |
97 |
|
79 |
38 |
79 |
96 |
|
Mean |
91 |
41.2 |
81.2 |
86.4 |
SStotal = |
9094.95 |
What is the SSwithin value?
360.58 |
||
1260.80 |
||
7834.15 |
||
9094.95 |
A researcher is interested in determining whether typists are most productive in the morning, at midday, in the evening, or late at night. To answer this question, the researcher recruits 20 participants and assigns 5 participants to be measured at each time of day. To evaluate productivity, the researcher measures words typed per minute at each time of day. Answer the following questions considering the data below (alpha = .05)
Morning |
Midday |
Evening |
Night |
|
99 |
42 |
80 |
82 |
|
80 |
32 |
83 |
78 |
|
99 |
45 |
94 |
79 |
|
98 |
49 |
70 |
97 |
|
79 |
38 |
79 |
96 |
|
Mean |
91 |
41.2 |
81.2 |
86.4 |
SStotal = |
9094.95 |
What is the observed test statistic; in other words, what is the value of the F-ratio?
4.56 |
||
10.33 |
||
26.75 |
||
33.14 |
A researcher is interested in determining whether typists are most productive in the morning, at midday, in the evening, or late at night. To answer this question, the researcher recruits 20 participants and assigns 5 participants to be measured at each time of day. To evaluate productivity, the researcher measures words typed per minute at each time of day. Answer the following questions considering the data below (alpha = .05)
Morning |
Midday |
Evening |
Night |
|
99 |
42 |
80 |
82 |
|
80 |
32 |
83 |
78 |
|
99 |
45 |
94 |
79 |
|
98 |
49 |
70 |
97 |
|
79 |
38 |
79 |
96 |
|
Mean |
91 |
41.2 |
81.2 |
86.4 |
SStotal = |
9094.95 |
What decision should be made regarding the null hypothesis?
Reject the null hypothesis |
||
Retain the null hypothesis |
||
Prove the null hypothesis |
Number of Columns = k = 4
Total Number Of Observations = N = 20
(1) Df Numerator = k - 1 = 4 - 1 = 3 (Option 3)
(2) Df Denominator = N - k = 20 - 4 = 16
(Option
3)
(3) The F critical Value for df N = 3 and df D = 16 is Option 1: 3.24
(4) SS Within = SUM [ n * (Mean - GM)2]
GM = (91 + 41.2 + 81.2 + 86.4) / 4 = 299.8 = 79.95
Therefore SS within = 5 * (91 - 79.5)2 + 5 * (41.2 - 79.5)2 + 5 * (81.2 - 79.5)2 + 5 * (86.4 - 79.5)2 = 7834.15 (Option 3)
________________________
(5) To Calculate the test statistic, we need MS Within / MS Error
MS within = SS within / df Numerator = 7834.15 / 3 = 2611.38
SSerror = SS Total - SS within = 9094.95 - 2611.38 = 1260.88
MS Error = SS error / df Denominator = 1260.88 / 16 = 78.8
Therefore F = 2611.38 / 78.8 = 33.14 (Option 4)
_________________________
(6) Since F stat is > Fcritical, Option 1: reject The Null Hypothesis.
______________________________
The ANOVA Table is below for your reference
Source | SS | DF | Mean Square | F | Fcv | p |
Between | 7834.15 | 3 | 2611.38 | 33.14 | 3.24 | 0.0000 |
Within/Error | 1260.80 | 16 | 78.80 | |||
Total | 9094.95 | 19 |