Calculate the amount (in mL) of 0.0462M calcium hydroxide that
would be required to completely react...
Calculate the amount (in mL) of 0.0462M calcium hydroxide that
would be required to completely react with 126.25 mL of a 0.0182M
HCl solution. do not enter the unit mL in your answer.
32.67 mL of a 0.1249 M sodium
hydroxide solution are required to completely react with a vitamin
C tablet with a mass of 908 mg . The potency
on the bottle of vitamin C tablets is 500 mg. The molecular weight
of vitamin C is 176.12 g/mol, and the molecular equation for the
reaction is HC6H7O6 (aq) + NaOH
(aq) → NaC6H7O6 (aq) +
H2O (l).
How many moles of OH- are used in the titration?
How many moles of vitamin C are...
1) Calculate the amount of 1.50 M Na2CO3 needed to react
completely with 25.0 mL of 0.500 M CaCl2.
2) Calculate the theoretical yield of chalk (calcium carbonate)
for each reaction (#1 & #2)—show all calculations. For reaction
#1 CaCl2 should be limiting and for reaction #2 Na2CO3 should be
limiting. You need to figure out how much sodium carbonate solution
you will use in your experiment
Na2CO3(aq) + CaCl2(aq)
àCaCO3(s) + 2NaCl(aq) (molecular
equation)
CO32–
(aq) + Ca2+(aq) àCaCO3(s) (net
ionic equation)
Limiting reactant(determining...
What volume (in mL) of a 0.150 MHNO3 solution is required to
completely react with 39.6 mL of a 0.118 MNa2CO3 solution according
to the following balanced chemical equation?
Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)
Express your answer with the appropriate units.
What volume (in mL) of a 0.125 M HNO3 solution is required to
completely react with 39.8 mL of a 0.102 M Na2CO3 solution
according to the following balanced chemical equation?
Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)
Express your answer with the appropriate units.
. What volume of 0.1 M NaOH is required to completely react with
50.00 mL of 0.1 M CH3COOH? (In other words, what volume is required
to reach the equivalence point?). Show work/reasoning.
A 10.0mL sample of calcium hydroxide solution required 26.85mL
of 0.225M hydrochloric acid for neutralization.
Calculate the molar concentration of the base.
2HCl(aq) + Ca(OH)2(aq) -> CaCl2(aq) + 2H2O(I)
For the following reaction, 29.8 grams of calcium hydroxide are
allowed to react with 24.6 grams of hydrochloric acid. calcium
hydroxide (aq) + hydrochloric acid (aq) calcium chloride (aq) +
water (l) What is the maximum amount of calcium chloride that can
be formed? grams What is the FORMULA for the limiting reagent? What
amount of the excess reagent remains after the reaction is
complete? grams