In: Statistics and Probability
In a study of perception, 143 men are tested and 24 are found
to have red/green color blindness. |
(a) | [2 marks] Find a 91% confidence interval for the true proportion of men from the sampled population that have this type of color blindness. |
(b) | [2 marks] Using the results from the above mentioned survey, how many men should be sampled to estimate the true proportion of men with this type of color blindness to within 1% with 97% confidence? |
Solution :
Given that,
a) Point estimate = sample proportion = = x / n = 24 / 143 = 0.168
1 - = 11 - 0.168 = 0.832
Z/2 = Z0.045 = 1.70
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.70 (((0.168 * 0.832) / 143)
= 0.053
A 91% confidence interval for population proportion p is ,
± E
= 0.168 ± 0.053
= ( 0.115, 0.221 )
b) Z/2 = Z0.015 = 2.17
sample size = n = (Z / 2 / E )2 * * (1 - )
= (2.17 / 0.01)2 * 0.168 * 0.832
= 6581.91
sample size = n = 6582