Question

The population of weights of a particular fruit is normally distributed, with a mean of 672 grams and a standard deviation of 35 grams. If 29 fruits are picked at random, then 4% of the time, their mean weight will be greater than how many grams? Round your answer to the nearest gram. to find answer

Answer 1

Given that,

mean = = 672

standard deviation = = 35

n = 29

= 672

= / n = 35 / 29=6.4993

Using standard normal table,

P(Z > z) =4 %

= 1 - P(Z < z) = 0.04  

= P(Z < z ) = 1 - 0.04

= P(Z < z ) = 0.96

= P(Z < 1.75) = 0.96

z = 1.75 using z table

Using z-score formula  

= z * +   

=1.75 *6.4993+672

= 683.37