In: Advanced Math
In triangle PQR right-angled at Q , PQ = 3 cm and PR = 6 cm. Determine ∠QPR
In triangle PQR right-angled at Q , PQ = 3 cm and PR = 6 cm
tan p = Opposite side / Adjacent side
Using Pythagorean theorem,
PR2 = PQ2 + QR2
62 = 32 + QR2
36 - 9 = QR2
QR2 = 27
QR = 3√3
tan p = PQ/QR
tan p = 3/√3
Multiplying both numerator and denominator by √3, we get
tan p = √3
∠QPR = 60°
<QPR=60°