The sides PQ, QR, and RP of a triangle PQR touch a circle, of
radius 4...
The sides PQ, QR, and RP of a triangle PQR touch a circle, of
radius 4 cm, at C, A, and B respectively. Given that QA = 8 cm, RA
= 6 cm, find the sides PQ and PR.
in the triangle PQR, the point S divides the line PQ in the
ratio 1:3, and T divides the line RQ in the ratio 3:2.
PR =a and PQ =b
express the following in terms of a and b
PS , SR, and TQ
Consider an equilateral triangle, inscribed in a circle of
radius a, with a point charge q at each vertex. The electric field
is zero at the center, but surprisingly there are three other
points inside the triangle where the field is also zero. Where are
they? Find the distance from these points to the center of the
circle.
Please just get the answer to E in terms of a, x, and y. I only
need you to solve up to...
Let a circle inside triangle DEF have a radius = 3, and let it
be tangent to EF at point Z. Suppose |EZ| = 6 and |FZ| = 7. What
are the lengths of d, e, and f?
4. By what factor does tripling the radius of a
circle
increase (a) the circumference of the circle? (b) the area
of the circle?
5. What are some of the advantages of scientific notation?
6. After which numeral is the decimal point usually placed
in scientific notation? What determines the number of
numerical digits written in scientific notation?
The centers of two circles are 4 cm apart, with one circle
having a radius of 3 cm and the other a radius of 2 cm. Find the
area of their intersection.
The “standard” bagel has always been the one obtained by
rotating the circle of radius 3/4 inch centered at (3/4 , 0) around
the line x = −1.
Recently, a Californian chef created a bagel with the same
circle but rotated around the line x = −2.
(a) Physically, what’s the difference between the two
bagels?
(b) What are the volumes of the standard and Californian
bagels?
Solve by using elimination. Find the center and the radius of
the circle whose graph passes through points (2,5) (-4,-3) and
(3,4). Use the given equation x^2 + y^2 + ax + by + c= 0