In: Mechanical Engineering
Given the following events in the table below and knowing that they are provided for a four stroke, spark-ignition engine running at 2500 RPM, please fill out the missing information.
Note that: BTDC=before top dead center, ATDC=after top dead center, ABDC=after bottom dead center, BBDC= before bottom dead center.
Process | Event | Duration (crank angle) | Duration(ms) |
Intake | 15 ˚BTDC to 60 ˚ABDC | ||
Compression | BDC to 30 ˚BTDC | ||
Combustion | 30 ˚BTDC to 30 ˚ATDC | ||
Expansion | TDC to BDC | ||
Exhaust | 60 ˚BBDC to 20 ˚ATDC | ||
One engine cycle |
Process | Event | Duration (crank angle) | Duration(ms) |
Intake | 15 ˚BTDC to 60 ˚ABDC | 225 | 15 |
Compression | BDC to 30 ˚BTDC | 150 | 10 |
Combustion | 30 ˚BTDC to 30 ˚ATDC | 60 | 4 |
Expansion | TDC to BDC | 180 | 12 |
Exhaust | 60 ˚BBDC to 20 ˚ATDC | 260 | 17.33 |
a 4 stroke engine completes in a cycle .A top to bottom covers
So for Intake 15 ˚BTDC to 60 ˚ABDC =15 ˚BTDC to BDC+BDC to 60 ˚ABDC=(180-15)+60=225
Compression =BDC to 30 ˚BTDC=180-30=150
Combustion =30 ˚BTDC to 30 ˚ATDC=30 ˚BTDC to TDC + TDC to 30 ˚ATDC=60
Expansion =TDC to BDC=180
Exhaust =60 ˚BBDC to 20 ˚ATDC=60+180+20=260
The total sum wont be equal to 720 because of overlapping of each process.
To find out time there is 2500 RPM.Two rotation completes a cycle ()
So one cycle=
for intake
similarly we can compute for other process also