If a solution containing 63.411 g of mercury(II) perchlorate is allowed to react completely with a...

If a solution containing 63.411 g of mercury(II) perchlorate is allowed to react completely with a solution containing 16.642 g of sodium dichromate, how many grams of solid precipitate will be formed?

Expert Solution

queen_honey_blossom answered 2 years ago

If a solution containing 37.525 g of mercury(II) perchlorate is allowed to react completely with a...

If a solution containing 37.525 g of mercury(II) perchlorate is allowed to react completely with a solution containing 12.026 g of sodium dichromate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 84.096 g of mercury(II) perchlorate is allowed to react completely with a...

If a solution containing 84.096 g of mercury(II) perchlorate is allowed to react completely with a solution containing 13.180 g of sodium sulfide, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 39.544 g of mercury(II) perchlorate is allowed to react completely with a...

If a solution containing 39.544 g of mercury(II) perchlorate is allowed to react completely with a solution containing 13.180 g of sodium dichromate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 17.91 g17.91 g of mercury(II) perchlorate is allowed to react completely with...

If a solution containing 17.91 g17.91 g of mercury(II) perchlorate is allowed to react completely with a solution containing 5.102 g5.102 g of sodium dichromate, how many grams of solid precipitate will be formed? mass: gg How many grams of the reactant in excess will remain after the reaction? mass: gg Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles....

If a solution containing 16.38 g of mercury (II) nitrate is allowed to react completely with...

If a solution containing 16.38 g of mercury (II) nitrate is allowed to react completely with a solution containing 51.02 g of sodium sulfate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 42.33 g of mercury(II) chlorate is allowed to react completely with a...

If a solution containing 42.33 g of mercury(II) chlorate is allowed to react completely with a solution containing 6.256 g of sodium sulfide, how many grams of solid precipitate will form? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 51.928 g of mercury(II) nitrate is allowed to react completely with a...

If a solution containing 51.928 g of mercury(II) nitrate is allowed to react completely with a solution containing 16.642 g of sodium dichromate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 78.296 g of mercury(II) acetate is allowed to react completely with a...

If a solution containing 78.296 g of mercury(II) acetate is allowed to react completely with a solution containing 13.180 g of sodium sulfide, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 22.90 g of mercury(II) nitrate is allowed to react completely with a...

If a solution containing 22.90 g of mercury(II) nitrate is allowed to react completely with a solution containing 7.410 g of sodium sulfate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

If a solution containing 35.10 g of mercury(II) chlorate is allowed to react completely with a...

If a solution containing 35.10 g of mercury(II) chlorate is allowed to react completely with a solution containing 6.256 g of sodium sulfide, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?

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